A) \[{{V}_{AB}}={{V}_{BC}}=100\,V\]
B) \[{{V}_{AB}}=75\,V,\ {{V}_{BC}}=25\ V\]
C) \[{{V}_{AB}}=25\,V,\ {{V}_{BC}}=75\ V\]
D) \[{{V}_{AB}}={{V}_{BC}}=50\ V\]
Correct Answer: C
Solution :
\[{{C}_{eq}}=\frac{(3+3)\times (1+1)}{(3+3)+(1+1)}+1=\left( \frac{6\times 2}{6+2} \right)\,+1\]\[=\frac{5}{2}\mu F\] \ \[Q=C\times V=\frac{5}{2}\times 100=250\mu C\] Charge in \[6\mu F\] branch \[=VC=\left( \frac{6\times 2}{6+2} \right)\,100\]\[=150\,\mu C\] \[{{V}_{AB}}=\frac{150}{6}=25\,V\] and \[{{V}_{BC}}=100-{{V}_{AB}}=75\,V\]You need to login to perform this action.
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