A) 9.9 W
B) 11 W
C) 8.8 W
D) 7.7 W
Correct Answer: A
Solution :
In figure (b) current through \[{{R}_{2}}=i-\frac{i}{10}=\frac{9i}{10}\] Potential difference across \[{{R}_{2}}\] = Potential difference across R Þ \[{{R}_{2}}\times \frac{9}{10}i=R\times \frac{i}{10}\] i.e. \[{{R}_{2}}=\frac{R}{9}=\frac{11}{9}\Omega \] \[{{R}_{eq}}=\frac{{{R}_{2}}\times R}{({{R}_{2}}+R)}=\frac{\frac{11}{9}\times \frac{11}{1}}{\frac{11}{9}+\frac{11}{1}}=\frac{11}{10}\Omega \] Total circuit resistance \[=\frac{11}{10}+{{R}_{1}}=R=11\]Þ \[{{R}_{1}}=9.9\Omega \]
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