Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर
JEE Main & Advanced
Physics
Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर
Question Bank
Critical Thinking
question_answer
In the adjoining circuit diagram each resistance is of 10 W. The current in the arm AD will be
A) \[\frac{2i}{5}\]
B) \[\frac{3i}{5}\]
C) \[\frac{4i}{5}\]
D) \[\frac{i}{5}\]
Correct Answer:
A
Solution :
Applying Kirchoff's law in mesh ABCDA \[-10(i-{{i}_{1}})-10{{i}_{2}}+20{{i}_{1}}=0\] Þ \[\,3{{i}_{1}}-{{i}_{2}}=i\] .......(i) and in mesh BEFCB \[-\,20\,(i-{{i}_{1}}-{{i}_{2}})+\,10\,({{i}_{1}}+{{i}_{2}})+10{{i}_{2}}=0\] Þ \[3{{i}_{1}}+4{{i}_{2}}=2i\] ......(ii) From equation (i) and (ii) \[{{i}_{1}}=\frac{2i}{5},\,{{i}_{2}}=\frac{i}{5}\]Þ \[{{i}_{AD}}=\frac{2i}{5}\]