A) \[{{x}^{\text{2}}}\]
B) x
C) \[{{x}^{\text{1}}}\]
D) \[{{x}^{\text{2}}}\]
Correct Answer: A
Solution :
\[U=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}\left( \frac{{{\varepsilon }_{0}}A}{x} \right)\,{{V}^{2}}\] \ \[\frac{dU}{dt}=\frac{1}{2}{{\varepsilon }_{0}}A{{V}^{2}}\left( -\frac{1}{{{x}^{2}}}\frac{dx}{dt} \right)\] Þ \[\frac{dU}{dt}\propto {{x}^{-2}}\]
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