A) \[1/(10\lambda )\]
B) \[1/(11\lambda )\]
C) \[11/(10\lambda )\]
D) \[1/(9\lambda )\]
Correct Answer: D
Solution :
\[{{N}_{1}}={{N}_{0}}{{e}^{-10\lambda t}}\]and \[{{N}_{2}}={{N}_{0}}{{e}^{-\lambda t}}\] \[\Rightarrow \frac{{{N}_{1}}}{{{N}_{2}}}=\frac{1}{e}={{e}^{-1}}={{e}^{(-10\lambda +\lambda )t}}={{e}^{-9\lambda t}}\Rightarrow t=\frac{1}{9\lambda }\].
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