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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    \[p{{K}_{a}}\] value for acetic acid at the experimental temperature is 5. The percentage hydrolysis of \[0.1\,\,M\] sodium acetate solution will be

    A)                 \[1\times {{10}^{-4}}\]  

    B)                 \[1\times {{10}^{-2}}\]

    C)                 \[1\times {{10}^{-3}}\]  

    D)                 \[1\times {{10}^{-3}}\]

    Correct Answer: B

    Solution :

               \[pKa=5\], so \[Ka=1\times {{10}^{-5}}\]                                 \[\alpha =\sqrt{\frac{Ka}{C}}=\sqrt{\frac{1\times {{10}^{-5}}}{0.1}}=1\times {{10}^{-2}}\]


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