A) \[0,\,a\,d\theta \]
B) \[a\,d\theta ,\,0\,\]
C) 0, 0
D) None of these
Correct Answer: B
Solution :
From the figure \[|\overrightarrow{OA}|\,=a\] and \[|\overrightarrow{OB}|\,=a\] Also from triangle rule \[\overrightarrow{OB}-\overrightarrow{OA}=\overrightarrow{AB}=\Delta \overrightarrow{a\,}\] \[\Rightarrow \,\,\,|\Delta \overrightarrow{a\,}|\,=AB\] Using angle \[=\frac{\text{arc}}{\text{radius}}\] Þ AB = a . dq So \[|\Delta \overrightarrow{a\,}|\,=\,a\,d\theta \] \[\Delta a\] means change in magnitude of vector i.e. \[|\overrightarrow{OB}|-|\overrightarrow{OA}|\] \[\Rightarrow \,\,\,a-a=0\] So \[\Delta a=0\]You need to login to perform this action.
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