JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Critical Thinking

  • question_answer
    Water boils in an electric kettle in 15 minutes after switching on. If the length of the heating wire is decreased to \[2/3\] of its initial value, then the same amount of water will boil with the same supply voltage in                          [MP PMT 1994]

    A)            15 minutes                            

    B)            12 minutes

    C)            10 minutes                            

    D)            8 minutes

    Correct Answer: C

    Solution :

                       \[H=\frac{{{V}^{2}}}{R}t\] Since supply voltage is same and equal amount of heat will produce, therefore \[\frac{{{R}_{1}}}{{{t}_{1}}}=\frac{{{R}_{2}}}{{{t}_{2}}}\] or \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{t}_{1}}}{{{t}_{2}}}\]                                                              .....(i) But \[R\propto l\]Þ \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\]                        .....(ii) By (i) and (ii),  \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{{{t}_{1}}}{{{t}_{2}}}\]                       .....(iii) Now \[{{l}_{2}}=\frac{2}{3}\,\,{{l}_{1}}\] Þ \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{3}{2}\] \ By equation (iii), \[\frac{3}{2}=\frac{15}{{{t}_{2}}}\] Þ \[{{t}_{2}}=10\,\,\]minutes


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