A) 800 V, 2A
B) 300 V, 2A
C) 220 V, 2.2 A
D) 100 V, 2A
Correct Answer: C
Solution :
\[{{V}^{2}}=V_{R}^{2}+{{({{V}_{L}}-{{V}_{C}})}^{2}}\]Þ \[{{V}_{R}}=V=220\,\,V\] Also \[i=\frac{220}{100}=2.2\,\,A\]
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