A) 100
B) 200
C) 4
D) \[\frac{1}{4}\]
Correct Answer: D
Solution :
\[({{r}_{m}})=\left( \frac{{{m}^{2}}}{Z} \right)\,(0.53{\AA})=(n\times 0.53{\AA})\] Þ \[\frac{{{m}^{2}}}{Z}=n\] m = 5 for \[_{100}F{{m}^{257}}\] (the outermost shell) and z = 100 Þ \[n=\frac{{{(5)}^{2}}}{100}=\frac{1}{4}\]You need to login to perform this action.
You will be redirected in
3 sec