A) \[\left( \frac{\pi }{2}-C \right)\]
B) 2C
C) \[\pi -2C\]
D) \[\pi -C\]
Correct Answer: C
Solution :
When the ray passes into the rarer medium, the deviation is \[\delta =\varphi -0\]. This can have a maximum value of \[\left( \frac{\pi }{2}-C \right)\] for \[\theta =C\] and \[\varphi =\frac{\pi }{2}\]. When total internal reflection occurs, the deviation is \[\delta =\pi -2\], the minimum value of \[\theta \] being \[C.\]The maximum value of \[\delta =\pi -2C\].You need to login to perform this action.
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