A) 176o
B) 4o
C) 178o
D) 2o
Correct Answer: C
Solution :
\[{{\delta }_{\Pr ism}}=(\mu -1)A=(1.5-1){{4}^{o}}={{2}^{o}}\] \[\therefore \]\[{{\delta }_{Total}}={{\delta }_{\Pr ism}}+{{\delta }_{Mirror}}\] \[=(\mu -1)A+(180-2i)={{2}^{o}}+(180-2\times 2)={{178}^{o}}\]You need to login to perform this action.
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