A) \[-\frac{Q}{4}(1+2\sqrt{2})\]
B) \[\frac{Q}{4}(1+2\sqrt{2})\]
C) \[-\frac{Q}{2}(1+2\sqrt{2})\]
D) \[\frac{Q}{2}(1+2\sqrt{2})\]
Correct Answer: B
Solution :
If all charges are in equilibrium, system is also in equilibrium. Charge at centre: charge q is in equilibrium because no net force acting on it corner charge: If we consider the charge at corner B. This charge will experience following forces \[{{F}_{A}}=k\frac{{{Q}^{2}}}{{{a}^{2}}},\]\[{{F}_{C}}=\frac{k{{Q}^{2}}}{{{a}^{2}}}\],\[{{F}_{D}}=\frac{k{{Q}^{2}}}{{{(a\sqrt{2})}^{2}}}\text{and}\,{{F}_{O}}=\frac{KQq}{{{(a\sqrt{2})}^{2}}}\]You need to login to perform this action.
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