A) \[\frac{{{\varepsilon }_{0}}AV}{d}.\frac{2{{\varepsilon }_{0}}AV}{d}\]
B) \[\frac{{{\varepsilon }_{0}}AV}{d}.\frac{2{{\varepsilon }_{0}}AV}{d}\]
C) \[\,\frac{{{\varepsilon }_{0}}AV}{d}.\frac{-2{{\varepsilon }_{0}}AV}{d}\]
D) \[\frac{-{{\varepsilon }_{0}}AV}{d}.\frac{-2{{\varepsilon }_{0}}AV}{d}\]
Correct Answer: C
Solution :
The given circuit can be redrawn as follows. All capacitors are identical and each having capacitance \[C=\frac{{{\varepsilon }_{0}}A}{d}\]You need to login to perform this action.
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