A) \[{{E}_{2}}={{E}_{1}}\]
B) \[{{E}_{2}}=2{{E}_{1}}\]
C) \[{{E}_{2}}=4{{E}_{1}}\]
D) \[{{E}_{2}}=16{{E}_{1}}\]
Correct Answer: C
Solution :
Energy (E) µ (Amplitude)2 (Frequency)2 Amplitude is same in both the cases, but frequency 2\[\omega \] in the second case is two times the frequency \[(\omega )\] in the first case. Hence \[{{E}_{2}}=4{{E}_{1}}\].You need to login to perform this action.
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