A) 0.012m
B) 0.025m
C) 0.05m
D) 0.024m
Correct Answer: B
Solution :
Let x be the end correction then according to question. \[\frac{v}{4({{l}_{1}}+x)}=\frac{3v}{4({{l}_{2}}+x)}\Rightarrow x=2.5\]\[cm=0.025\]\[m\].You need to login to perform this action.
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