A) \[6\times {{10}^{-6}}m\]
B) \[6.6\times {{10}^{-6}}m\]
C) \[3.138\times {{10}^{-7}}m\]
D) \[3.144\times {{10}^{-7}}m\]
Correct Answer: A
Solution :
P is the position of 11th bright fringe from Q. From central position O, P will be the position of 10th bright fringe. Path difference between the waves reaching at P = S1B =10 l = 10 ´ 6000 ´ 10?10 = 6 ´ 10?6m.You need to login to perform this action.
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