A) 2
B) 5
C) 4
D) None of these
Correct Answer: A
Solution :
Maximum energy is liberated for transition \[{{E}_{n}}\to 1\] and minimum energy for \[{{E}_{n}}\to {{E}_{n-1}}\] Hence \[\frac{{{E}_{1}}}{{{n}^{2}}}-{{E}_{1}}=52.224\,eV\] ??(i) and \[\frac{{{E}_{1}}}{{{n}^{2}}}-\frac{{{E}_{1}}}{{{(n-1)}^{2}}}=1.224\,eV\] ?..(ii) Solving equations (i) and (ii) we get \[{{E}_{1}}=-54.4\,eV\] and \[n=5\] Now \[{{E}_{1}}=-\frac{13.6\,{{Z}^{2}}}{{{1}^{2}}}=-54.4\,eV.\]Hence \[Z=2\]You need to login to perform this action.
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