A) Zero
B) \[\frac{25C{{V}^{2}}}{6}\]
C) \[\frac{3C{{V}^{2}}}{2}\]
D) \[\frac{9C{{V}^{2}}}{2}\]
Correct Answer: C
Solution :
Total charge \[=(2C)\,(2V)+(C)\,(-V)=3CV\] \ Common potential \[=\frac{3CV}{3C}=V\] \ Energy \[=\frac{1}{2}(3C)\,{{(V)}^{2}}=\frac{3}{2}C{{V}^{2}}\]You need to login to perform this action.
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