A) 51 m
B) 60 m
C) 70 m
D) All the above
Correct Answer: A
Solution :
As limit of resolution \[\Delta \theta =\frac{1}{Resolving\ Power(RP)}\]; and if x is the distance between points on the surface of moon which is at a distance r from the telescope. \[\Delta \theta =\frac{x}{r}\] So \[\Delta \theta =\frac{1}{RP}=\frac{x}{r}i.e.\ x=\frac{r}{RP}=\frac{r}{d/1.22\ \lambda }\]\[\Rightarrow x=\frac{1.22\ \lambda r}{d}\] \[=\frac{1.22\times 5500\times {{10}^{-10}}\times (3.8\times {{10}^{8}})}{500\times {{10}^{-2}}}=51\ m\]You need to login to perform this action.
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