A) \[PbC{{l}_{4}}<PbC{{l}_{2}}<CaC{{l}_{2}}<NaCl\]
B) \[PbC{{l}_{2}}<PbC{{l}_{4}}<CaC{{l}_{2}}<NaCl\]
C) \[PbC{{l}_{2}}<PbC{{l}_{4}}<NaCl<CaC{{l}_{2}}\]
D) \[PbC{{l}_{4}}<PbC{{l}_{2}}<NaCl<CaC{{l}_{2}}\]
Correct Answer: A
Solution :
\[PbC{{l}_{4}}<PbC{{l}_{2}}<CaC{{l}_{2}}<NaCl\] is the increasing order of ionic character.You need to login to perform this action.
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