JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Critical Thinking

  • question_answer
    A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each division reads 1 volt, the resistance in ohms needed to be connected in series with the coil will be               [AIEEE 2005]

    A)            99995                                      

    B)            9995

    C)            \[{{10}^{3}}\]                       

    D)            \[{{10}^{5}}\]

    Correct Answer: B

    Solution :

                       Voltage sensitivity \[=\frac{\text{Current sensitivity}}{\text{Resistance of galvanometer}\,\text{G}}\] Þ \[G=\frac{10}{2}=5\,\Omega \]. Here \[{{i}_{g}}=\] Full scale deflection current \[=\frac{150}{10}=15\,mA\]. V = Voltage to be measured = 150 ´ 1 = 150 V. Hence \[R=\frac{V}{{{i}_{g}}}-G=\frac{150}{15\times {{10}^{-3}}}-5=9995\,\Omega \].


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