A) \[1.09\times {{10}^{-15}}\ mole/litre\]
B) \[1.72\times {{10}^{-15}}\ mole/litre\]
C) \[2.3\times {{10}^{-16}}\ mole/litre\]
D) \[1.65\times {{10}^{-36}}\ mole/litre\]
Correct Answer: A
Solution :
\[{{K}_{sp}}=[A{{s}^{3+}}][{{S}^{2-}}]\], \[S=\sqrt[5]{\frac{{{K}_{sp}}}{108}}\] \[=\sqrt[5]{\frac{2.8\times {{10}^{-72}}}{108}}\]\[=1.09\times {{10}^{-15}}\]
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