A) With \[{{S}_{1}}\]closed, \[{{V}_{1}}=15\,V,\ {{V}_{2}}=20\ V\]
B) With \[{{S}_{3}}\] closed \[{{V}_{1}}={{V}_{2}}=25V\]
C) With \[{{S}_{1}}\] and \[{{S}_{2}}\] closed \[{{V}_{1}}={{V}_{2}}=0\]
D) With\[{{S}_{1}}\]and \[{{S}_{3}}\]closed, \[{{V}_{1}}=30\,V,\ {{V}_{2}}=20\,V\]
Correct Answer: D
Solution :
Charges on capacitors are \[{{Q}_{1}}=30\times 2=6pC\] and \[{{Q}_{2}}=20\times 3=60pC\] or \[{{Q}_{1}}={{Q}_{2}}=Q\,(\text{say})\] The situation is situation is similar as the two capacitors in series are first charged with a battery of emf 50 V and then disconnected
\ when \[{{S}_{\text{3}}}\] is closed \[{{V}_{1}}=30V\] and \[{{V}_{2}}=20V\]
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