A) 9 A
B) 0.9 A
C) \[\frac{1}{9}A\]
D) \[\frac{1}{0.9}A\]
Correct Answer: B
Solution :
No current flows through the capacitor branch in steady state. Total current supplied by the battery i \[=\frac{6}{2.8+1.2}=\frac{3}{2}\]. Current through 2 W resistor \[=\frac{3}{2}\times \frac{3}{5}=0.9A\]
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