| List I (Compound) | List II (Oxidation state of N) | ||
| A | \[N{{O}_{2}}\] | 1 | +5 |
| B | \[HNO\] | 2 | -3 |
| C | \[N{{H}_{3}}\] | 3 | +4 |
| D | \[{{N}_{2}}{{O}_{5}}\] | 4 | +1 |
A) A-2 B-3 C-4 D-1
B) A-3 B-1 C-2 D-4
C) A-3 B-4 C-2 D-1
D) A-2 B-3 C-1 D-4
Correct Answer: C
Solution :
\[\overset{*}{\mathop{N}}\,{{O}_{2}}\];\[x-4=0\];\[x=+\,4\] \[H\overset{*}{\mathop{N}}\,O\];\[1+x-2=0\];\[x=+1\] \[\overset{*\,\,\,\,\,\,}{\mathop{N{{H}_{3}}}}\,\]; \[x+3=0\]; \[x=-3\] \[{{\overset{*}{\mathop{N}}\,}_{2}}{{O}_{5}}\]; \[2x-10=0\];\[2x=10\]; \[x=\frac{10}{2}\]; x = 5.
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