A) 2.0 cm above P
B) 1.5 cm above P
C) 2.0 cm below P
D) 1 cm above P
Correct Answer: D
Solution :
The two slabs will shift the image a distance \[d=2\,\left( 1-\frac{1}{\mu } \right)\,t=2\,\left( 1-\frac{1}{1.5} \right)\,\left( 1.5 \right)=1\,cm\] Therefore, final image will be 1 cm above point P.
You need to login to perform this action.
You will be redirected in
3 sec
