A) Zero
B) \[q/2\]
C) q
D) \[2q\]
Correct Answer: A
Solution :
The \[\pm q\] charges appearing on the inner surfaces of A, are bound charges. As B is uncharged initially, as it is isolated, the charges on A will not be affected on closing the switch S. No charge will flow in to B.You need to login to perform this action.
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