JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Critical Thinking

  • question_answer
    At 298K a 0.1 M \[C{{H}_{3}}COOH\]solution is 1.34% ionized. The ionization constant \[{{K}_{a}}\] for acetic acid will be  [AMU 2002; AFMC 2005]

    A)                 \[1.82\times {{10}^{-5}}\]            

    B)                 \[18.2\times {{10}^{-5}}\]

    C)                 \[0.182\times {{10}^{-5}}\]         

    D)                 None of these  

    Correct Answer: A

    Solution :

                    \[K=c{{\alpha }^{2}}=0.1\times {{\left( \frac{1.34}{100} \right)}^{2}}=1.8\times {{10}^{-5}}\].


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