A) 80%
B) 89%
C) 11%
D) 20%
Correct Answer: A
Solution :
Specific rotation \[(\alpha )=\frac{\theta }{l\,c}\Rightarrow c=\frac{\theta \,}{\alpha l}=\frac{0.4}{0.01\times 0.25}=160\,kg/{{m}^{3}}\] Now percentage purity of sugar solution \[=\frac{160}{200}\times 100=80%\]You need to login to perform this action.
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