A) \[\frac{\alpha }{\lambda }\]
B) \[{{N}_{0}}+\frac{\alpha }{\lambda }\]
C) N0
D) \[\frac{\lambda }{\alpha }+{{N}_{0}}\]
Correct Answer: A
Solution :
Maximum number of nuclei will be present when rate of decay = rate of formation Þ \[\lambda N=\alpha \] Þ \[N=\frac{\alpha }{\lambda }\]
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