A) 0.36 MeV
B) 0.41 MeV
C) 0.48 MeV
D) 1.32 MeV
Correct Answer: A
Solution :
\[{{m}_{0}}{{c}^{2}}=0.54\,MeV\]and K.E. = \[m{{c}^{2}}-{{m}_{0}}{{c}^{2}}\] Also \[m=\frac{{{m}_{0}}}{\sqrt{1-\frac{{{v}^{2}}}{{{c}^{2}}}}}=\frac{{{m}_{0}}}{\sqrt{1-{{(0.8)}^{2}}}}=\frac{{{m}_{0}}}{0.6}\] \ \[E=m{{c}^{2}}=\frac{{{m}_{0}}}{0.6}{{c}^{2}}=\frac{{{m}_{0}}c}{0.6}=\frac{0.5\,H}{0.6}=0.9\,MeV\] \ K.E.= (0.9 ? 0.54) = 0.36 MeV.
You need to login to perform this action.
You will be redirected in
3 sec
