JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Critical Thinking

  • question_answer
    A 4 mF capacitor, a resistance of 2.5 MW is in series with 12 V battery. Find the time after which the potential difference across the capacitor is 3 times the potential difference across the resistor. [Given ln(2)= 0.693] [IIT-JEE (Screening) 2005]

    A)            13.86 s

    B)                                      6.93 s

    C)                 7 s          

    D)                 14 s

    Correct Answer: A

    Solution :

               \[{{V}_{R}}=\frac{{{V}_{0}}}{4}\] = \[{{V}_{0}}{{e}^{-\frac{t}{RC}}}\]Þ\[\frac{1}{4}\] = \[{{e}^{-\frac{t}{10}}}\] Þ \[4={{e}^{\frac{t}{10}}}\] Þ \[{{\log }_{e}}4=\frac{t}{10}\] Þ \[t=10\log 4\] = 13.86 s \[(RC=\text{ 2}.\text{5}\times \text{1}{{0}^{\text{6}}}\times \text{4}\times \text{1}{{0}^{-\text{6}}}=\text{ 1}0)\]


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