A) 50 W
B) 100 W
C) 200 W
D) 400 W
Correct Answer: D
Solution :
\[\tan \varphi =\frac{{{X}_{L}}}{R}=\frac{{{X}_{C}}}{R}\Rightarrow \tan {{60}^{o}}=\frac{{{X}_{L}}}{R}=\frac{{{X}_{C}}}{R}\] \[\Rightarrow {{X}_{L}}={{X}_{C}}=\sqrt{3}\ R\] i.e. \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}=R\] So average power \[P=\frac{{{V}^{2}}}{R}=\frac{200\times 200}{100}\]= 400WYou need to login to perform this action.
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