JEE Main & Advanced Mathematics Straight Line Question Bank Critical Thinking

  • question_answer Let PS be the median of the triangle with vertices \[P(2,\ 2),\ Q(6,\ -\ 1)\]and \[R(7,\ 3)\]. The equation of the line passing through (1,? 1) and parallel to PS is  [IIT Screening 2000]

    A)            \[2x-9y-7=0\]                            

    B)            \[2x-9y-11=0\]

    C)            \[2x+9y-11=0\]                         

    D)            \[2x+9y+7=0\]

    Correct Answer: D

    Solution :

               S = midpoint of \[QR=\left( \frac{6+7}{2},\,\frac{-1+3}{2} \right)=\left( \frac{13}{2},\,1 \right)\]                    \ ?m? of \[PS=\frac{2-1}{2-\frac{13}{2}}=-\frac{2}{9}\],                    \ The required equation is \[y+1=\frac{-2}{9}(x-1)\]                    i.e.,\[2x+9y+7=0\].


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