A) \[{{C}_{2}}{{H}_{6}}\] (excess) \[+C{{l}_{2}}\xrightarrow{UV\text{ Light}}\]
B) \[{{C}_{2}}{{H}_{6}}\] + \[C{{l}_{2}}\underset{\text{ Room}\,\text{temp}\text{.}}{\mathop{\xrightarrow{\text{Dark}}}}\,\]
C) \[{{C}_{2}}{{H}_{6}}+C{{l}_{2}}\text{ (excess) }\xrightarrow{UV\text{ Light}}\]
D) \[{{C}_{2}}{{H}_{6}}+C{{l}_{2}}\xrightarrow{UV\text{ Light}}\]
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{6}}(\text{excess)}+C{{l}_{2}}\xrightarrow{U.V.\text{Light}}\underset{\text{(Major product)}}{\mathop{\underset{\text{Ethyl chloride}}{\mathop{{{C}_{2}}{{H}_{5}}Cl}}\,}}\,+HCl\]
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