A) \[\frac{d}{v}\] sec
B) \[\frac{\sqrt{2d}}{v}\] sec
C) \[\frac{d}{\sqrt{2v}}\] sec
D) \[\frac{d}{2v}\] sec
Correct Answer: A
Solution :
It is obvious from considerations of symmetry that at any moment of time all of the persons will be at the corners of square whose side gradually decreases (see fig.) and so they will finally meet at the centre of the square O.You need to login to perform this action.
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