A) \[\frac{1}{2}mgR\]
B) 2 mgR
C) mgR
D) \[\frac{1}{4}mgR\]
Correct Answer: A
Solution :
Gain in potential energy \[\Delta U=\frac{mgh}{1+\frac{h}{R}}\] If \[h=R\] then \[\Delta U=\frac{mgR}{1+\frac{R}{R}}=\frac{1}{2}mgR\]You need to login to perform this action.
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