A) \[{{\cos }^{-1}}\sqrt{\mu _{2}^{2}-\mu _{1}^{2}}\]
B) \[{{\sin }^{-1}}\sqrt{\mu _{1}^{2}-\mu _{2}^{2}}\]
C) \[{{\tan }^{-1}}\sqrt{\mu _{1}^{2}-\mu _{2}^{2}}\]
D) \[{{\sec }^{-1}}\sqrt{\mu _{1}^{2}-\mu _{2}^{2}}\]
Correct Answer: B
Solution :
Here the requirement is that \[i>c\] \[\Rightarrow \,\,\sin i>\sin c\,\,\,\Rightarrow \,\,\sin i>\frac{{{\mu }_{2}}}{{{\mu }_{1}}}\] ?..(i) From Snell?s law \[{{\mu }_{1}}=\frac{\sin \alpha }{\sin r}\] ?.(ii)You need to login to perform this action.
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