JEE Main & Advanced Physics Vectors Question Bank Critical Thinking

  • question_answer
    The length of second's hand in watch is 1 cm. The change in velocity of its tip in 15 seconds is                      [MP PMT 1987]

    A)             Zero                                          

    B)             \[\frac{\pi }{30\sqrt{2}}\,\,cm/\sec \]

    C)             \[\frac{\pi }{30}\,\,cm/\sec \]

    D)                                         \[\frac{\pi \sqrt{2}}{30}\,\,cm/\sec \]

    Correct Answer: D

    Solution :

                           \[\Delta v=2v\sin \left( \frac{90{}^\circ }{2} \right)=2v\sin 45{}^\circ \]\[=2v\times \frac{1}{\sqrt{2}}=\sqrt{2}v\]             \[=\sqrt{2}\times r\omega =\sqrt{2}\times 1\times \frac{2\pi }{60}=\frac{\sqrt{2}\pi }{\grave{\ }30}\ cm/s\]


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