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JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Critical Thinking

  • question_answer
    The voltage of an ac source varies with time according to the equation \[V=100\sin \ 100\pi t\cos 100\pi t\] where \[t\] is in seconds and V is in volts. Then                                                                          [MP PMT 1996; 2000]

    A)            The peak voltage of the source is 100 volts

    B)            The peak voltage of the source is 50 volts

    C)            The peak voltage of the source is \[100/\sqrt{2}\]volts

    D)            The frequency of the source is 50 Hz

    Correct Answer: B

    Solution :

                       \[V=50\times 2\,\sin \,100\pi t\,\cos \,100\pi t=50\sin 200\pi t\]            \[\Rightarrow \,\,{{V}_{0}}=50\,Volts\] and \[\nu =100Hz\]


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