JEE Main & Advanced Mathematics Straight Line Question Bank Critical Thinking

  • question_answer The equation of straight line passing through \[(-a,\ 0)\] and making the triangle with axes of area ?T? is      [RPET 1987]

    A)            \[2Tx+{{a}^{2}}y+2aT=0\]         

    B)            \[2Tx-{{a}^{2}}y+2aT=0\]

    C)            \[2Tx-{{a}^{2}}y-2aT=0\]          

    D)            None of these

    Correct Answer: B

    Solution :

               If the line cuts off the axes at A and B, then area of triangle is \[\frac{1}{2}\times OA\times OB=T\]                    Þ \[\frac{1}{2}.a.OB=T\Rightarrow OB=\frac{2T}{a}\]                    Hence the equation of line is \[\frac{x}{-a}+\frac{y}{2T/a}=1\]                    \[\Rightarrow 2Tx-{{a}^{2}}y+2aT=0\].

You need to login to perform this action.
You will be redirected in 3 sec spinner