A) Zero
B) \[\frac{1}{\sqrt{2}}\,m/{{s}^{2}}\,N-W\]
C) \[\frac{1}{\sqrt{2}}\,m/{{s}^{2}}\,N-E\]
D) \[\frac{1}{\sqrt{2}}\,m/{{s}^{2}}\,S-W\]
Correct Answer: B
Solution :
\[\Delta v=2v\sin \left( \frac{\theta }{2} \right)=2\times 5\times \sin 45{}^\circ \]=\[\frac{10}{\sqrt{2}}\] \ \[a=\frac{\Delta v}{\Delta t}=\frac{10/\sqrt{2}}{10}=\frac{1}{\sqrt{2}}\ m/{{s}^{2}}\]
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