A) \[P=W\,\tan \theta \]
B) \[\overrightarrow{T}+\overrightarrow{P}+\overrightarrow{W}=0\]
C) \[{{T}^{2}}={{P}^{2}}+{{W}^{2}}\]
D) \[T=P+W\]
Correct Answer: D
Solution :
As the metal sphere is in equilibrium under the effect of three forces therefore \[\overrightarrow{T}+\overrightarrow{P}+\overrightarrow{W}=0\] From the figure \[T\cos \theta =W\] ?(i) \[T\sin \theta =P\] ?(ii) From equation (i) and (ii) we get \[P=W\,\tan \theta \] and \[{{T}^{2}}={{P}^{2}}+{{W}^{2}}\]You need to login to perform this action.
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