A) \[{{W}_{1}}>{{W}_{2}}\]
B) \[{{W}_{1}}={{W}_{2}}\]
C) \[{{W}_{1}}<{{W}_{2}}\]
D) \[{{W}_{2}}=({{W}_{1}}/2)\]
Correct Answer: C
Solution :
As the coefficient of cubical expansion of metal is less as compared to the coefficient of cubical expansion of liquid, we may neglect the expansion of metal ball. So when the ball is immersed in alcohol at 0ºC, it displaces some volume V of alcohol at 0ºC and has weight W1. \[\therefore \] W1 = W0 ? Vr0g where W0 = weight of ball in air Similarly, W2 = W0 ? Vr50g where r0 = density of alcohol at 0ºC and r50 = density of alcohol at 50ºC As r50 < r0, Þ W2 > W1 or W1 < W2
You need to login to perform this action.
You will be redirected in
3 sec
