A) 4 Mg/K
B) 2 Mg/K
C) Mg/K
D) Mg/2K
Correct Answer: B
Solution :
Let x be the maximum extension of the spring. From energy conservation Loss in gravitational potential energy = Gain in potential energy of spring \[Mgx=\frac{1}{2}K{{x}^{2}}\] \[\Rightarrow x=\frac{2Mg}{K}\]You need to login to perform this action.
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