A) 2/3
B) 5/6
C) 6/5
D) 3/2
Correct Answer: C
Solution :
\[y=K{{t}^{2}}\]Þ\[\frac{{{d}^{2}}y}{d{{t}^{2}}}={{a}_{y}}=2K\]= 2 ´ 1=2m/s2 (\[\because \]K= 1m/s2) Now, \[{{T}_{1}}=2\pi \sqrt{\frac{l}{g}}\] and \[{{T}_{2}}=2\pi \sqrt{\frac{l}{(g+{{a}_{y}})}}\] Dividing, \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{g+{{a}_{y}}}{g}}\] Þ \[\sqrt{\frac{6}{5}}\]Þ \[\frac{T_{1}^{2}}{T_{2}^{2}}=\frac{6}{5}\]You need to login to perform this action.
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