A) \[\frac{5}{4}R\]
B) \[\frac{2}{3}R\]
C) \[\frac{3}{4}R\]
D) \[\frac{3}{2}R\]
Correct Answer: D
Solution :
Time period of a physical pendulum \[T=2\pi \sqrt{\frac{{{I}_{0}}}{mgd}}=2\pi \sqrt{\frac{\left( \frac{1}{2}m{{R}^{2}}+m{{R}^{2}} \right)}{mgR}}\] \[=2\pi \sqrt{\frac{3R}{2g}}\] ?..(i) \[{{T}_{simple\ pendulum}}=2\pi \sqrt{\frac{l}{g}}\] ?..(ii) Equating (i) and (ii), \[l=\frac{3}{2}R.\]You need to login to perform this action.
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