A) \[\frac{59}{91}\]
B) \[\frac{44}{91}\]
C) \[\frac{51}{91}\]
D) \[\frac{32}{91}\]
Correct Answer: B
Solution :
Probability [Person \[A\] will die in 30 years] \[=\frac{8}{8+5}\] \[P(A)=\frac{8}{13}\Rightarrow P(\bar{A})=\frac{5}{13}\] Similarly, \[P(B)=\frac{4}{7}\Rightarrow P(\bar{B})=\frac{3}{7}\] There are two ways in which one person is alive after 30 years. \[\bar{A}B\] and \[A\bar{B}\] and event are independent. So, required probability \[=P(\bar{A})\,.\,P(B)+P(A)\,.\,P(\bar{B})\]\[=\frac{5}{13}\times \frac{4}{7}+\frac{8}{13}\times \frac{3}{7}=\frac{44}{91}.\]
You need to login to perform this action.
You will be redirected in
3 sec
