A) \[1\times {{10}^{-2}}J/T\]
B) \[2.08\times {{10}^{-2}}J/T\]
C) \[3.08\times {{10}^{-2}}J/T\]
D) \[1.52\times {{10}^{-2}}J/T\]
Correct Answer: B
Solution :
Relation for dipole moment is, \[M=I\times V\]. Volume of the cylinder \[V=\pi r{{r}^{2}}l\], Where r is the radius and l is the length of the cylinder, then dipole moment, \[M=I\pi {{r}^{2}}l=(5.30\times {{10}^{3}})\times \frac{22}{7}\times {{(0.5\times {{10}^{-2}})}^{2}}(5\times {{10}^{-2}})\] \[=2.08\times {{10}^{-2}}J/T\]
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